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Re: [TEKNIK] number of me - script problem



2010/4/14 Erling A. Jacobsen <sslug@sslug>:
> On Wed, 2010-04-14 at 14:15 +0200, Martin Møller Skarbiniks Pedersen
> wrote:
>> Hejsa,
>>   På solaris og AIX bruger jeg flg. lille kode-stump:
>>
>> #!/bin/bash
>>
>> NUM_OF_ME=$(ps -ef | grep num_of_me.sh |wc -l )
>> echo $NUM_OF_ME
>>
>> if [[ $NUM_OF_ME -gt 1 ]] ; then echo already running ; exit ; fi
>>
>> [...]
>>
>>
>> Men under linux er NUM_OF_ME lig 3, selvom der ikke kører andre kopier
>> af scriptet.
>> Hvad sker der lige og hvad kan det bedst løses, så det virker ens på
>> alle unix-platforme ?
>
> Det har formentlig ikke så meget at gøre med linux kontra ikke-linux,
> men mere med at du også tæller grep processen med.
>
> Jeg plejer altid at tilføje en "| grep -v grep" efter den første grep,
> så passer pengene. Det kan sikkert også gøres mere sofistikeret.
>

Næh. Det giver stadigvæk for mange selvom jeg tilføjer
grep -v grep


 
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