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Eller en kortere udgave (inspireret af Jacobs svar): ls | sed 's/-r[0-9]\+$//' | sort -u Hilsen Johnny :o) torsdag den 27. Marts 2008 kvad Johnny Ernst Nielsen: > Så skal du måske kigge på om din afart af sed har særlige > matchningsregler, for på min maskine virker Jens' forslag nøjagtigt > som du vil have det. > > $ ls > harry-r100 harry-r2 kurt-r10-r11 sally-r1 sally-r10 > > $ ls | sed 's/\(.\+\)-r[0-9]\+/\1/' | sort -u > harry > kurt-r10 > sally > > $ sed --version > GNU sed version 4.1.5 > > Hilsen Johnny :o) > > torsdag den 27. Marts 2008 kvad Hans Ole Hansen: > > Tak > > Men hvad nu hvis filnavnet er kurt-r10-r11, og det jeg ønsker så > > bliver kurt-r10 > > > > Dvs kommandoen skal kun slette de sidste tegn her -r11 . > > > > "Hans Ole Hansen" <sslug@sslug> skrev i en meddelelse > > news:sslug@sslug > > > > > Jeg har nogle filer sally-r1, sally-r10, harry-r100, harry-r2 > > > > > > Jeg vil gerne generere en liste hvor de første tegne fra > > > filnavnet indtil -r[0-9]+ optræder kun engang. > > > I ovennævnte eksempel skulle listen i såfald blive > > > > > > sally > > > harry > > > > > > Hvordan gør jeg det. Jeg tror at jeg skal bruge noget lign > > > > > > ls | sed 's/\(.+\)r[0-9]+/\1/' | sort -u > > > > > > Men min sed kommando virker ikke som ønsket. Hvad gør jeg galt?
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