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Re: [PROGRAMMERING] Hvorfor er 0 == 1? SOLVED



Jens Bang wrote:
> On Monday 10 September 2007, Jørgen Heesche wrote:
>   
>> Dette script
>>
>> #/bin/bash
>> FileCount=0
>> for X in $(ls -d backup* 2> /dev/null)
>> do
>>      FileCount=$((FileCount+1))
>> done
>> echo FileCount=$FileCount
>>
>> virker med 0, 1, 2, .. n directories, det er ikke nødvendigt at pipe til wc
>>     
>
> Jeg markerede koden og kopierede den over i en fil kaldet dirtest.sh, som jeg 
> gemte i et tomt directory. Jeg skiftede ned i samme directory som filen. Her 
> er resultatet:
>
> sslug@sslug:~/backups/test$ chmod u+x dirtest.sh
> sslug@sslug:~/backups/test$ ./dirtest.sh
> FileCount=0
> sslug@sslug:~/backups/test$ mkdir backup0000
> sslug@sslug:~/backups/test$ ./dirtest.sh
> ./dirtest.sh: line 5:  : command not found
> FileCount=0
> sslug@sslug:~/backups/test$
>
> Så noget går galt, jeg forstår bare ikke hvad. Det er den linie der tæller 
> variablen op der fejler, og den har tidligere virket i den form, så nu er jeg 
> ægte forvirret.
>
>   
Sikker på at der ikke står:

     $FileCount=$((FileCount+1))




 
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