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Anders Søndergaard <sslug@sslug> writes: > [input tal]. Hvis jeg gør sådan her: Er der væsentlige dele af koden du har udeladt? > int *pointer,tal,hent; > > pointer = (int *) malloc(sizeof(int)); Her allokerer du plads til ét heltal. > ... > hent = find_numbers(pointer,tal); Jeg går ikke ud fra at find_numbers allokerer mere plads? > while (hent>0) { > printf("%i\n",pointer[hent-1]); /* tallene kommer fint ud */ > } Derfor bruger du her noget plads du rent faktisk ikke har allokeret for du har kun allokeret pointer[0]. > Jeg har prøvet mig frem, og fundet ud af at fejlen sker når de to mallocs: > pointer = (int *) malloc(sizeof(int)); > pointerto = (int *) malloc(sizeof(int)); > står under hinanden. Sikkert fordi at pointer og pointerto bliver allokeret lige efter hinanden. -- Peter Makholm | Yes, you can fight it, but in the end the ultimate sslug@sslug | goal of life is to have fun http://hacking.dk | -- Linus Torvalds
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